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●VB6提供了许多的好用字符串处理函数。
●用法：传回字符串 = Replace(被取代字符串, 要找的字符串, 取代成的字符串, 开始位置, 取代几组)
Private Sub Command1_Click()
- Dim MyStr As String
- MyStr = "1234567890123456789012345678901234567890"
- Print Replace(MyStr, "90", "九零")
End Sub
●输出结果："12345678九零12345678九零12345678九零12345678九零"
Private Sub Command1_Click()
- Dim MyStr As String
- MyStr = "1234567890123456789012345678901234567890"
- Print Replace(MyStr, "90", "九零", 11, 2)
End Sub
●输出结果："123456789012345678九零12345678九零1234567890"
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